Doubt if Blues want Nash at 6m a year for two years. (or any team)

Not sure why you think no team would want Nash at a 6m cap hit. With all the overpaid contracts that were given out 2 days ago Nash at 6m is a steal. He is one of the best two way players in the league. One season removed from 42 goals. All you people that think he is a bad player and "doesn't show up when needed" are simply stupid. Nash is still one of the best power forwards in the league that is consistent in all zones. You're a leafs fan so clearly you know nothing about him. Stop making assumptions on a player that probably haven't watched enough to evaluate.

OK, I put it another way. Next year the Blues have their own RFAs to sign. They certainly don't need Nash at 6m gumming up the cap. If Nash if so great as you indicate, maybe the Rangers should keep him.
Maybe you're right, I'm a Leaf fan and I know nothing about Nash. Clearly you know the Rangers (hence the ever trading of Nash), but obviously you know very little of the 29 teams in the league.

Nash at $6MM for 2 yrs is a great deal for a contender. All depends on the return and fit though. R shot D values are clearly stupid as hell, so don't think that Blues deal works, especially with picks coming back (Blues cap issues not withstanding). Shatty is probably a trade deadline deal next year as #STL won't get full value this summer unless acquiring team is sure of an extension.
I suspect Gorton is trying to move Nash w/out retaining $ which is going to be tough. I think Nash could get a very nice return, but this off season has shown it won't be for a top-4 D man. Complicating the issue is Nash's M-NTC list. Apparently no Canadian teams are on his list which removes a whole lot of plausible destinations. Not to mention, he loves NYC. Given that, his list probably contains teams that are the least likely to be in need of his services.
Given all of the above, I think likely offers are 1st/2nd packages which Rangers obviously won't take. My guess is he gets moved at the deadline in Feb or not at all.